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Ravey · 09-25-2005, 07:20 PM

Does anyone know how to solve absolute value equations? I know how to graph them. But I can't solve them. Problems like...

3y=|2x-9|

explain it to me please, my head hurts.

Hollow · 09-25-2005, 07:32 PM

what are you supposed to solve for? looks to me like it's already simplified.

Ravey · 09-25-2005, 07:34 PM

You have to make a t chart. Like a x|y chart thingy.

Like at this site: http://www.purplemath.com/modules/graphabs.htm

but from looking at that site I still don't get it. lol

IMakeBurgers · 09-25-2005, 07:35 PM

Ok, it's probably easier to graph it and look at the graph...

Looking at the graph, it seems like X is All real numbers and y is all reals greater than or equal to 0

Ravey · 09-25-2005, 07:37 PM

How come 1/3 isn't inside the |'s?

Ravey · 09-25-2005, 07:37 PM

Quote:

Originally Posted by IMakeBurgers

Oops, I graphed..

noooo keep it there. lol I hate math so much.

Ravey · 09-25-2005, 07:40 PM

I'm stll confused. I don't get how you got the points. Can you show me what the t chart would look like?

3y=|2x-9|

so you devide it all by 3...

y=|2/3x-3| is what I get lol

IMakeBurgers · 09-25-2005, 07:40 PM

Quote:

Originally Posted by Ravey

How come 1/3 isn't inside the |'s?

I just didn't distribute, that's all. It's also..

y = |(2/3)x-3|

Ravey · 09-25-2005, 07:41 PM

Quote:

Originally Posted by IMakeBurgers

I just didn't distribute, that's all. It's also..

y = |(2/3)x-3|

So how would you know the vertext? It's 0, right?

IMakeBurgers · 09-25-2005, 07:42 PM

Just because it'll be easier for me to write it, I will....Give me a second.

Ravey · 09-25-2005, 07:42 PM

Quote:

Originally Posted by IMakeBurgers

Just because it'll be easier for me to write it, I will....Give me a second.

Thank you so much.

IMakeBurgers · 09-25-2005, 07:45 PM

Quote:

Originally Posted by Ravey

So how would you know the vertext? It's 0, right?

It gives no number for the y part of the vertex, so it's assumed to be 0..

y = |2/3x - 3 | + 0

So your vertex is (3,0). Then just do rise over run w/ your slope and you get the graph. I've never done a T chart for this type of equation, I just look at the graph and can tell where the points are and arent

Ravey · 09-25-2005, 07:47 PM

Quote:

Originally Posted by IMakeBurgers

It gives no number for the y part of the vertex, so it's assumed to be 0..

y = |2/3x - 3 | + 0

So your vertex is (3,0). Then just do rise over run w/ your slope and you get the graph. I've never done a T chart for this type of equation, I just look at the graph and can tell where the points are and arent

Ohh my teacher showed it to us with tcharts. She put that...

y=|2x-5| as a t chart is

X|Y
0 5
2.5 0
4 3

she said from your vertex you choose a number higher and one lower or something that I didn't understand. lol

PZelda · 09-25-2005, 07:48 PM

BAHHHHH. This kind of formula was easy for me to solve in Algebra 2, but alas that was 3 years ago. I still have my notes though...So it wouldn't take long for me to remember. [/dork]

Ravey · 09-25-2005, 07:49 PM

For 2/3 rise over run is go up 2 right 3, right? And that's it?

09-25-2005, 07:20 PM	#1
Ravey Member Forum Icon Join Date: Apr 02, 2003 Posts: 53,025	Math Help Does anyone know how to solve absolute value equations? I know how to graph them. But I can't solve them. Problems like... 3y=\|2x-9\| explain it to me please, my head hurts.

09-25-2005, 07:35 PM	#4
IMakeBurgers Borderline Amazing Senior Member Join Date: Oct 11, 2001 Location: Fayetteville, NC Posts: 1,595	Ok, it's probably easier to graph it and look at the graph... Looking at the graph, it seems like X is All real numbers and y is all reals greater than or equal to 0 Attached Images
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09-25-2005, 07:48 PM	#14
PZelda Two Valeries! <3 Forum Addict Join Date: Jul 15, 2002 Location: I'm STILL missing NYC. :( Posts: 78,223	BAHHHHH. This kind of formula was easy for me to solve in Algebra 2, but alas that was 3 years ago. I still have my notes though...So it wouldn't take long for me to remember. [/dork]
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09-25-2005, 07:32 PM	#2
Hollow Member Forum Superstar Join Date: Dec 16, 2001 Posts: 30,406	what are you supposed to solve for? looks to me like it's already simplified.

09-25-2005, 07:34 PM	#3
Ravey Member Forum Icon Join Date: Apr 02, 2003 Posts: 53,025	You have to make a t chart. Like a x\|y chart thingy. Like at this site: http://www.purplemath.com/modules/graphabs.htm but from looking at that site I still don't get it. lol

09-25-2005, 07:37 PM	#5
Ravey Member Forum Icon Join Date: Apr 02, 2003 Posts: 53,025	How come 1/3 isn't inside the \|'s?

09-25-2005, 07:40 PM	#7
Ravey Member Forum Icon Join Date: Apr 02, 2003 Posts: 53,025	I'm stll confused. I don't get how you got the points. Can you show me what the t chart would look like? 3y=\|2x-9\| so you devide it all by 3... y=\|2/3x-3\| is what I get lol

09-25-2005, 07:42 PM	#10
IMakeBurgers Borderline Amazing Senior Member Join Date: Oct 11, 2001 Location: Fayetteville, NC Posts: 1,595	Just because it'll be easier for me to write it, I will....Give me a second.

09-25-2005, 07:49 PM	#15
Ravey Member Forum Icon Join Date: Apr 02, 2003 Posts: 53,025	For 2/3 rise over run is go up 2 right 3, right? And that's it?