Thread: Percentage help
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Old 09-21-2003, 12:12 PM   #2
BrandonS
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Default Re: Percentage help

Quote:
Originally posted by Miss Karly
I'm in 9th grade and can do Algebra, Geometry and some basic Trig, meanwhile I sit here for a half hour trying to figure out this problem on your average percentages. Oh yes... I'm brilliant all right. [/sarcasm]

Can anyone help me on this?! It would be forever appreciated... and you'd get a cookie too.

#22. During a special sale, the price of a television is reduced by 10% the first day of the sale and an additional 4% for each successive day of the sale.

a. If the sale price of the TV after 2 days is $80, what was the original price of the TV? Show how you found your answer.
I'll get you started with part (a). It's kind of hard with only the keyboard symbols, but if unknown original price is X, then:

X (.9)(.96) = 80 (Note: .9 comes from 10% off 1st day and .96 comes from 4% off 2nd day)

Dividing both sides of the equation by (.9)(.96):

X = 80/((.9)(.96)) = 80/.864 = 92.593... or 92.59 to the nearest cent

Also, I'm using the standard algebra notation where putting numbers next to each other implies multiplication even without a "times" symbol.
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